How do I find f(3) given the function f(x) = 2a + 3x + 9ax where ‘a’ is a non-zero constant?

To find f(3) for the function f(x) = 2a + 3x + 9ax, we will substitute x = 3 into the function.

1. Start with the function:

f(x) = 2a + 3x + 9ax

2. Substitute x with 3:

f(3) = 2a + 3(3) + 9a(3)

3. Now calculate the individual terms:

  • 3(3) = 9
  • 9a(3) = 27a

This gives us:

f(3) = 2a + 9 + 27a

4. Combine the like terms:

f(3) = (2a + 27a) + 9 = 29a + 9

Finally, the value of f(3) is:

f(3) = 29a + 9

Remember, since a is a constant that is not equal to zero, this expression will provide a unique value for any specific value of a.

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