How do I solve for b2 in the equation 12h(b1b2) when a equals 16 h and b1 equals 3?

To solve for b2 in the equation 12h(b1b2), we start by examining the variables and their given values.

We know that:

Given the equation:

12h(b1b2) = a

First, we’ll substitute a with 16h:

12h(b1b2) = 16h

Next, we can divide both sides of the equation by h to simplify. Assuming h ≠ 0 (as division by zero is undefined):

12(b1b2) = 16

Now, we substitute the value of b1 (which is 3) into the equation:

12(3b2) = 16

This simplifies to:

36b2 = 16

Now, we can solve for b2 by dividing both sides by 36:

b2 = 16 / 36

Simplifying the fraction:

b2 = 4 / 9

Therefore, the value of b2 is 4/9.