How do you determine the rate of change of the area of a circle when its circumference is increasing at a rate of 5 meters per minute and the radius is 4 meters?

To find the rate of change of the area of a circle when its circumference is increasing, we can use the relationships between circumference, radius, and area.

Step 1: Understand the relationship

The circumference C of a circle is given by the formula:

C = 2πr

where r is the radius. The area A of a circle is given by:

A = πr²

Step 2: Determine what’s known

We know that the circumference is increasing at a rate of 5 meters per minute:

\frac{dC}{dt} = 5 ext{ m/min}

At the moment we want to analyze, the radius is:

r = 4 ext{ m}

Step 3: Differentiate the circumference

To find the rate of change of the radius \frac{dr}{dt}, we first differentiate the circumference formula with respect to time:

\frac{dC}{dt} = 2π\frac{dr}{dt}

Now, we can solve for \frac{dr}{dt}:

\frac{dr}{dt} = \frac{1}{2π} \frac{dC}{dt}

Substituting the known rate:

\frac{dr}{dt} = \frac{1}{2π} \times 5 = \frac{5}{2π} ext{ m/min}

Step 4: Differentiate the area

Next, we differentiate the area formula:

\frac{dA}{dt} = 2πr \frac{dr}{dt}

Step 5: Substitute known values

Now we substitute r = 4 meters and \frac{dr}{dt} = \frac{5}{2π}:

\frac{dA}{dt} = 2π(4) \times \frac{5}{2π}

Calculating this gives:

\frac{dA}{dt} = 8 \times 5 = 40 ext{ m²/min}

Conclusion

Therefore, the rate of change of the area of the circle when the radius is 4 meters is:

40 square meters per minute.

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