How do you determine the slope of the line described by the equation 3x + 2y = 8 in the XY plane?

To find the slope of the line from the equation 3x + 2y = 8, we first need to rearrange it into the slope-intercept form, which is given by:

y = mx + b

where m represents the slope and b represents the y-intercept.

Starting with the original equation:

3x + 2y = 8

We want to isolate y. First, subtract 3x from both sides:

2y = -3x + 8

Next, divide every term by 2 to solve for y:

y = -\frac{3}{2}x + 4

Now, it’s clear that the equation is in the slope-intercept form y = mx + b, where:

  • m (the slope) is -3/2
  • b (the y-intercept) is 4

Thus, the slope of the line represented by the equation 3x + 2y = 8 is -\frac{3}{2}.

This means for every 2 units you move to the right along the x-axis, the line will move 3 units down along the y-axis.

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