How do you find csc(x) if sin(x) * cot(x) = cos(x) * √3?

To find csc(x) given the equation sin(x) * cot(x) = cos(x) * √3, we can start rewriting the equation using trigonometric identities.

First, recall the identity for cot(x): cot(x) = cos(x) / sin(x). Thus, we can substitute it into our equation:

sin(x) * (cos(x) / sin(x)) = cos(x) * √3

This simplifies to:

cos(x) = cos(x) * √3

Assuming cos(x) ≠ 0, we can divide both sides by cos(x):

1 = √3

However, this is not true, indicating that either cos(x) = 0 or there is no solution under these conditions. If we set cos(x) = 0, then we are looking for the values of x where cosine equals zero, specifically where:

x = π/2 + nπ, where n is any integer.

Now, given that csc(x) is the reciprocal of sin(x), we can find values for sin(x) at these points:

  • For x = π/2: sin(π/2) = 1, so csc(π/2) = 1.
  • For x = 3π/2: sin(3π/2) = -1, so csc(3π/2) = -1.

Thus, csc(x) can take on values of 1 and -1 at these angles.

To summarize:

  • If cos(x) = 0, then csc(x) = 1 or csc(x) = -1.
  • Given the initial equation does not lead to valid cosine results, the only valid solutions come from cos(x) = 0.

Therefore, we conclude that the possible values for csc(x) are 1 and -1.

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