How do you find the equation of a line in slope-intercept form that passes through the points (6, 1) and (3, 2)?

To find the equation of the line in slope-intercept form (y = mx + b) that passes through the points (6, 1) and (3, 2), we will follow these steps:

Step 1: Calculate the slope (m)

The slope (m) of a line can be found using the formula:

m = (y2 – y1) / (x2 – x1)

Here, we can label the points as follows:

  • (x1, y1) = (6, 1)
  • (x2, y2) = (3, 2)

Substituting the values into the slope formula:

m = (2 – 1) / (3 – 6) = 1 / -3 = -1/3

Step 2: Use the slope to find the y-intercept (b)

To find the y-intercept (b), we can use the slope-intercept form of the equation and substitute one of the points. We know:

y = mx + b

Using the point (6, 1):

  • 1 = (-1/3)(6) + b

This simplifies to:

1 = -2 + b

To solve for b, add 2 to both sides:

b = 1 + 2 = 3

Step 3: Write the equation of the line

Now that we have both the slope (m) and the y-intercept (b), we can write the equation of the line:

y = -1/3x + 3

Conclusion

The equation of the line in slope-intercept form that passes through the points (6, 1) and (3, 2) is:

y = -1/3x + 3

This equation tells us that for every increase of 1 in x, y decreases by 1/3, and the line crosses the y-axis at the point (0, 3).

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