How do you find the equation of the line in slope-intercept form that passes through the points (3, 1) and (1, 5)?

To find the equation of the line in slope-intercept form (which is y = mx + b, where m is the slope and b is the y-intercept), we first need to determine the slope (m) of the line that passes through the two given points: (3, 1) and (1, 5).

The formula to calculate the slope m between two points (x_1, y_1) and (x_2, y_2) is:

m = (y_2 – y_1) / (x_2 – x_1)

Here, we can assign: (x_1, y_1) = (3, 1) and (x_2, y_2) = (1, 5).

Now plug in the values:

m = (5 – 1) / (1 – 3) = 4 / -2 = -2

So, the slope m is -2.

Next, we need to find the y-intercept b. We can use the slope-intercept form of the equation and one of the points to solve for b. Let’s use the point (3, 1).

Substituting the values into the slope-intercept equation:

1 = -2(3) + b

This simplifies to:

1 = -6 + b

Now, solve for b:

b = 1 + 6 = 7

Now that we have both the slope (-2) and the y-intercept (7), we can write the equation of the line:

y = -2x + 7

In conclusion, the equation of the line in slope-intercept form that passes through the points (3, 1) and (1, 5) is:

y = -2x + 7

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