How do you find the linearization of the function f(x) = sin(x) at the point a = p/3?

To find the linearization of the function f(x) = sin(x) at the point a = π/3, we need to follow a few steps.

Step 1: Determine the function value at a

First, we evaluate the function at the point a = π/3:

f(π/3) = sin(π/3) = √3/2

Step 2: Compute the derivative of f(x)

Next, we find the derivative of the function f(x). The derivative of sin(x) is cos(x):

f'(x) = cos(x)

Step 3: Evaluate the derivative at a

Now we need to evaluate the derivative at the point a = π/3:

f'(π/3) = cos(π/3) = 1/2

Step 4: Use the linearization formula

The linearization L(x) of the function f(x) at the point a is given by the formula:

L(x) = f(a) + f'(a)(x – a)

Step 5: Substitute the values

Now we can plug in the values we computed:

L(x) = (√3/2) + (1/2)(x – π/3)

Final form of the linearization

Thus, the linearization of the function f(x) = sin(x) at the point a = π/3 is:

L(x) = (√3/2) + (1/2)(x – π/3)

This linear function approximates the behavior of the sine function near the point x = π/3.

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