How do you find the probability of the union of two mutually exclusive events A and B if the probabilities of A and B are given as 0.2 and 0.6 respectively?

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To determine the probability of the union of two mutually exclusive events A and B, we can use the formula:

P(A ∪ B) = P(A) + P(B)

In our case, we have:

  • P(A) = 0.2
  • P(B) = 0.6

Since events A and B are mutually exclusive, this means that they cannot happen at the same time. Therefore, we can simply add their probabilities:

P(A ∪ B) = P(A) + P(B) = 0.2 + 0.6 = 0.8

Thus, the probability of either event A or event B occurring is 0.8. This is a straightforward calculation given the properties of mutually exclusive events, making these types of probability problems manageable.

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