How do you find the slope and y-intercept of a line given its equation in the form ax + by = c?

To find the slope and y-intercept of a line represented by the equation of the form ax + by = c, you need to rearrange the equation into the slope-intercept form, which is y = mx + b. In this formula:

  • m represents the slope of the line.
  • b represents the y-intercept, where the line crosses the y-axis.

Here are the steps to do this:

  1. Start with the given equation: ax + by = c.
  2. Isolate by on one side of the equation: by = c – ax.
  3. Next, divide every term by b (assuming b is not zero) to solve for y:
    y = -\frac{a}{b}x + \frac{c}{b}.

In this form:

  • The slope m is equal to -\frac{a}{b}.
  • The y-intercept b is equal to \frac{c}{b}.

Example: Let’s say you have the equation 2x + 3y = 6:

  1. Isolate 3y: 3y = 6 – 2x.
  2. Divide by 3: y = -\frac{2}{3}x + 2.

From this, you can see:

  • The slope (m) is -\frac{2}{3}.
  • The y-intercept (b) is 2 (which means the line crosses the y-axis at the point (0, 2)).

Now you know how to find the slope and y-intercept for any line given its standard equation!

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