How do you graph the function f(x) = x² + 4x + 5?

To graph the function f(x) = x² + 4x + 5, follow these steps:

1. Understand the Function:

This is a quadratic function in the form of f(x) = ax² + bx + c, where:

  • a = 1
  • b = 4
  • c = 5

Since a > 0, the parabola opens upwards.

2. Find the Vertex:

The vertex of a quadratic function can be found using the formula:

x = -b / (2a)

Substituting the values of a and b:

x = -4 / (2 * 1) = -2

Now, substitute x = -2 back into the original function to find the y-coordinate:

f(-2) = (-2)² + 4(-2) + 5 = 4 – 8 + 5 = 1

So, the vertex is at the point (-2, 1).

3. Find the Y-Intercept:

The y-intercept is calculated by setting x = 0:

f(0) = 0² + 4(0) + 5 = 5

This means the y-intercept is at the point (0, 5).

4. Find the X-Intercepts:

To find the x-intercepts, set f(x) = 0:

x² + 4x + 5 = 0

This quadratic does not factor easily, so we can use the quadratic formula:

x = (-b ± √(b² – 4ac)) / (2a)

Substituting the values:

b² – 4ac = 4² – 4(1)(5) = 16 – 20 = -4

Since the discriminant is negative (-4), it means there are no real x-intercepts; instead, the parabola lies completely above the x-axis.

5. Plotting Points:

To graph the function accurately, you can plot additional points:

  • For x = -3: f(-3) = 9 – 12 + 5 = 2 → Point: (-3, 2)
  • For x = -1: f(-1) = 1 – 4 + 5 = 2 → Point: (-1, 2)
  • For x = 1: f(1) = 1 + 4 + 5 = 10 → Point: (1, 10)

6. Sketch the Graph:

Now that you have:

  • Vertex: (-2, 1)
  • Y-Intercept: (0, 5)
  • Additional Points: (-3, 2), (-1, 2), (1, 10)

You can draw the parabola. Start by marking the vertex, y-intercept, and the points you plotted. Then, sketch a smooth curve through these points, ensuring the parabola opens upwards.

Conclusion:

By identifying the key features of the function f(x) = x² + 4x + 5, you can create an accurate graph that reflects its behavior. Enjoy the process of visualizing this quadratic function!

Leave a Comment