How do you write an equation in point-slope form for a line that goes through the point (8, 3) with a slope of 8?

To write an equation in point-slope form, you can use the formula:

• y – y₁ = m(x – x₁)

Where:

• (x₁, y₁) is a point on the line (in this case, (8, 3))
• m is the slope of the line (which is 8 here)

Now, we can substitute the values into the formula:

• Point: (8, 3) → x₁ = 8, y₁ = 3
• Slope: m = 8

Substituting these values gives us:

y - 3 = 8(x - 8)

This equation, y – 3 = 8(x – 8), is in point-slope form. You can use this equation to find any point on the line or further manipulate it if needed. For example, you can convert it to slope-intercept form (y = mx + b) if required:

y - 3 = 8x - 64  →  y = 8x - 61

So, the line through the point (8, 3) with a slope of 8 can be expressed in point-slope form as:

y - 3 = 8(x - 8)

And in slope-intercept form as:

y = 8x - 61