How many days will B take to finish the work if A takes 6 days less than B and both can complete the work together in 4 days?

Let the number of days taken by B to finish the work alone be denoted as x. Therefore, the number of days taken by A to finish the work alone will be x – 6 (since A takes 6 days less than B).

When A and B work together, their combined work rate can be expressed as:

  • Work rate of A = (1 / (x – 6)) (work per day)
  • Work rate of B = (1 / x) (work per day)

Thus, their combined work rate is:

Combined work rate = (1 / (x – 6)) + (1 / x)

Since A and B together can finish the work in 4 days, their combined work rate is also equal to:

1/4 (work per day)

Equating the two expressions, we get:

(1 / (x – 6)) + (1 / x) = 1/4

Now, to solve for x, we’ll find a common denominator on the left side:

x(x – 6) is the common denominator. Thus, we have:

(x + (x – 6)) / (x(x – 6)) = 1/4

This simplifies to:

(2x – 6) / (x^2 – 6x) = 1/4

Cross-multiplying gives us:

4(2x – 6) = x^2 – 6x

Expanding both sides produces:

8x – 24 = x^2 – 6x

Rearranging leads to:

x^2 – 14x + 24 = 0

This quadratic equation can be factored as:

(x – 12)(x – 2) = 0

Setting each factor to zero gives the possible solutions:

  • x – 12 = 0x = 12
  • x – 2 = 0x = 2

Since x represents the number of days taken by B, we can only consider positive and reasonable solutions. The first solution x = 12 is valid, while x = 2 is not feasible since A would take -4 days to complete the work, which doesn’t make sense.

Therefore, B takes 12 days to finish the work alone.

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