If a varies inversely as b and a is 3 when b is 4, what is the value of b when a is 48?

To solve this problem, we start by understanding the concept of inverse variation. If a varies inversely as b, it means that as one of the variables increases, the other decreases. Mathematically, this relationship can be represented as:

a × b = k

where k is a constant.

1. **Determine the constant (k):** Given that a = 3 when b = 4, we can plug these values into the equation to find k.

3 × 4 = k

This simplifies to:

k = 12

2. **Express the relationship:** Now that we know the constant, we can express the relationship between a and b as:

a × b = 12

3. **Find b when a = 48:** We need to find the value of b when a = 48. Using the equation we obtained:

48 × b = 12

To isolate b, we can divide both sides of the equation by 48:

b = \frac{12}{48}

This simplifies to:

b = \frac{1}{4}

Thus, the value of b when a = 48 is:

b = 0.25

In summary, when a = 48, b evaluates to 0.25.

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