What are the factors of the expression 2x^2 + 3x + 54?

To find the factors of the quadratic expression 2x² + 3x + 54, we will use the technique of factoring by grouping or the quadratic formula if necessary.

First, we can identify the coefficients from the given expression:

  • a: 2 (the coefficient of x²)
  • b: 3 (the coefficient of x)
  • c: 54 (the constant term)

Next, we can calculate the discriminant (D) of the quadratic equation using the formula:

D = b² – 4ac

In this case:

  • D = (3)² – 4(2)(54)
  • D = 9 – 432
  • D = -423

Since the discriminant is negative (D < 0), this indicates that the quadratic expression does not have real roots and hence cannot be factored into linear factors with real coefficients.

This means that 2x² + 3x + 54 is either prime or requires complex numbers for factoring. Therefore, express it as:

(2x + 9 + i√423/2)(2x + 9 – i√423/2)

In conclusion, the expression 2x² + 3x + 54 does not have real factorable components and can only be expressed in complex terms.

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