To find the first six terms of the sequence defined by a_n = a_(n-1) + 8 with the initial condition a_1 = 4, we will calculate each subsequent term based on the previous term.
1. First term: a_1 = 4
2. Second term: a_2 = a_1 + 8 = 4 + 8 = 12
3. Third term: a_3 = a_2 + 8 = 12 + 8 = 20
4. Fourth term: a_4 = a_3 + 8 = 20 + 8 = 28
5. Fifth term: a_5 = a_4 + 8 = 28 + 8 = 36
6. Sixth term: a_6 = a_5 + 8 = 36 + 8 = 44
Thus, the first six terms of the sequence are: 4, 12, 20, 28, 36, 44.