What are the focus and directrix of the parabola given by the equation y = 112x²?

The equation of the parabola given is y = 112x². This is a standard form of a parabola that opens upwards. To find the focus and directrix, we first need to rewrite the equation in the standard form of a parabola.

The standard form for a parabola that opens upwards is:

y = 4p(x – h)² + k

In this equation:

  • (h, k) is the vertex of the parabola,
  • p is the distance from the vertex to the focus.

Comparing y = 112x² with the standard form, we can see that:

  • h = 0
  • k = 0
  • 4p = 112

From the equation 4p = 112, we can solve for p:

p = 112 / 4 = 28

This means that the focus is located at a distance of 28 units above the vertex, which is at (0, 0).

Therefore, the coordinates of the focus are:

(0, 28)

Next, we need to find the equation of the directrix, which is a horizontal line located p units below the vertex.

Since the vertex is at (0, 0) and p = 28, the directrix is:

y = 0 – 28 = -28

In conclusion:

  • Focus: (0, 28)
  • Directrix: y = -28

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