What are the implications of g being an even function and h being an even function of g?

To understand the implications of g being an even function and h being an even function of g, let us first define what we mean by an even function.

An even function is one that satisfies the condition f(-x) = f(x) for all x in its domain. This symmetry about the y-axis means that the function produces the same output for both the positive and negative values of x.

Now, if we define g as an even function, we can write:

  • g(-x) = g(x)

Next, when we talk about h being an even function of gh is also symmetric around the y-axis. Therefore, for h applied to g, the following holds true:

  • h(g(-x)) = h(g(x))

Since we know that g(-x) = g(x), we can substitute this into the equation:

  • h(g(-x)) = h(g(x))
  • h(g(-x)) = h(g(x))

This means that when h is an even function of g, the property of evenness is preserved. Therefore, if you take any even function g and apply an even function h, the resulting function will also be even.

In conclusion, if both g and h are even functions, the composition or the resultant function of h applied to g remains even:

  • h(g(x)) is even

This relationship illustrates the concept of symmetry in mathematics and showcases the beauty of function properties when combined in specific ways.

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