To solve the equation x6 + 6x3 + 5 = 0 using factoring, we can start by recognizing that this polynomial can be simplified through substitution.
Let y = x3. Then, the equation transforms into:
y2 + 6y + 5 = 0
This is now a quadratic equation in terms of y. We can factor this quadratic:
(y + 1)(y + 5) = 0
Setting each factor equal to zero gives us:
- y + 1 = 0 → y = -1
- y + 5 = 0 → y = -5
Now we substitute back for y
- x3 = -1 → x = -1
- x3 = -5 → x = –
oot{3}{5}
Therefore, the solutions to the original equation x6 + 6x3 + 5 = 0 are:
- x = -1
- x = –
oot{3}{5}
In conclusion, we successfully factored the polynomial after a substitution, allowing us to find the roots of the equation efficiently!