To find the three consecutive multiples of 8 whose sum is 888, we can start by defining the multiples. Let the first multiple of 8 be represented as x. The next two consecutive multiples can be expressed as x + 8 and x + 16.
Now, we can write an equation representing the sum of these three multiples:
x + (x + 8) + (x + 16) = 888
Combining like terms, we have:
3x + 24 = 888
To isolate 3x, we subtract 24 from both sides:
3x = 888 – 24
3x = 864
Next, we divide by 3 to solve for x:
x = 864 / 3
x = 288
Now that we have the first multiple, we can find the other two:
- First Multiple: 288
- Second Multiple: 288 + 8 = 296
- Third Multiple: 288 + 16 = 304
Therefore, the three consecutive multiples of 8 that sum up to 888 are 288, 296, and 304.