What are the values of x in the quadratic equation x² + 6x + 9?

To find the values of x in the quadratic equation x² + 6x + 9 = 0, we can apply the factoring method as this equation is a perfect square trinomial.

First, we rewrite the equation:

x² + 6x + 9 = 0

Next, we recognize that the quadratic can be expressed as:

(x + 3)² = 0

This means that:

x + 3 = 0

Now, solving for x, we subtract 3 from both sides:

x = -3

Since the quadratic is a perfect square, this means there is only one value for x:

x = -3

In conclusion, the solution to the quadratic equation x² + 6x + 9 = 0 is:

  • x = -3

This indicates that -3 is a repeated root of the equation, and the parabola represented by the equation only touches the x-axis at this point.

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