What is the 20th term of the sequence that starts with 4, 8, 16, 32?

The sequence you’ve provided is a geometric sequence where each term is obtained by multiplying the previous term by a constant factor. Let’s break it down:

The first few terms are:

  • 1st term: 4
  • 2nd term: 8
  • 3rd term: 16
  • 4th term: 32

Looking closely, we can see that:

  • 8 = 4 × 2
  • 16 = 8 × 2
  • 32 = 16 × 2

This shows that the common ratio (r) is 2. We can express the nth term of a geometric sequence using the formula:

nth term = a × r^(n-1)

where:

  • a is the first term of the sequence (4 in this case)
  • r is the common ratio (2)
  • n is the term number

Now, to find the 20th term, we substitute the values:

20th term = 4 × 2^(20-1)

This simplifies to:

20th term = 4 × 2^19

Calculating 2^19, we find it equals 524288. Therefore:

20th term = 4 × 524288 = 2097152

So, the 20th term of the sequence is 2,097,152.

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