What is the approximate amount of syrup in 45 gulab jamuns shaped like a cylinder with two hemispherical ends?

To find the approximate amount of syrup in 45 gulab jamuns, we first need to determine the volume of a single gulab jamun, which can be approximated as a cylinder topped with two hemispherical ends.

The formula for the volume of a cylinder is:

  • Vcylinder = πr2h

And the formula for the volume of a sphere is:

  • Vsphere = (4/3)πr3

Since a gulab jamun has two hemispherical ends, the volume of the two hemispheres combined is equal to the volume of a full sphere:

  • Vhemispheres = (4/3)πr3

Now, to find the total volume of one gulab jamun:

  • Vtotal = Vcylinder + Vhemispheres
  • = πr2h + (4/3)πr3

For example, if we assume a typical gulab jamun has a radius r of 2 cm and a height h of 4 cm (the height of the cylindrical part), we can substitute these values:

  • Vcylinder = π(22)(4) = 16π cm3
  • Vhemispheres = (4/3)π(23) = (4/3)π(8) = (32/3)π cm3

This gives the total volume of one gulab jamun:

  • Vtotal = 16π + (32/3)π = (48/3 + 32/3)π = (80/3)π cm3

Calculating this gives:

  • Vtotal ≈ 83.3 cm3 (using π ≈ 3.14)

Now, for 45 gulab jamuns, we simply multiply:

  • Total Volume ≈ 45 * 83.3 cm3 ≈ 3748.5 cm3

Assuming that the syrup fills about 70% of the volume of each gulab jamun, the total amount of syrup can be approximated as:

  • Syrup Volume ≈ 0.7 * 3748.5 cm3 ≈ 2624 cm3

In conclusion, you can expect approximately 2624 cm3 of syrup for 45 gulab jamuns shaped like cylinders with two hemispherical ends, assuming the stated dimensions and the syrup filling ratio.

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