What is the center of the circle represented by the equation x² + y² = 42?

The equation given is in the form of a circle’s equation in standard form, which is typically expressed as:

x² + y² = r²

In this case, we can see that the equation is:

x² + y² = 42

To find the center of the circle, we recall that the standard form of a circle centered at point (h, k) is:

(x - h)² + (y - k)² = r²

Here, (h, k) represents the coordinates of the center, and r is the radius of the circle.

In the given equation, the terms x² and y² imply that h = 0 and k = 0, as there are no additional terms subtracted from x or y. Thus, the center of the circle is at the origin:

(0, 0)

Moreover, we can determine the radius by taking the square root of the right-hand side of the equation:

r = √42

Summarizing, the center of the circle represented by the equation x² + y² = 42 is:

(0, 0)

This means that the circle is centered at the origin of the Cartesian plane.

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