What is the equation of a circle with center at (2, 3) and radius of 3 units?

To find the equation of a circle, we use the standard form of the circle’s equation, which is:

(x – h)2 + (y – k)2 = r2

Where:

  • (h, k) is the center of the circle.
  • r is the radius of the circle.

In your case, the center of the circle is given as (2, 3) and the radius is 3 units.

Thus, substituting these values into the equation:

  • h = 2
  • k = 3
  • r = 3

The equation becomes:

(x – 2)2 + (y – 3)2 = 32

Which simplifies to:

(x – 2)2 + (y – 3)2 = 9

So the final equation of the circle is:

(x – 2)2 + (y – 3)2 = 9

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