What is the equation of a circle with its center at the origin and a radius of 16?

The equation of a circle is commonly expressed in the standard form:

(x – h)² + (y – k)² = r²

In this formula:

  • (h, k) represents the coordinates of the center of the circle.
  • r is the radius of the circle.

For our specific case:

  • The center of the circle is at the origin, which means (h, k) = (0, 0).
  • The radius r is given as 16.

Now, substituting these values into the standard equation:

(x – 0)² + (y – 0)² = 16²

This simplifies to:

x² + y² = 256

Therefore, the equation of the circle with its center at the origin and a radius of 16 is x² + y² = 256.

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