What is the equation of a circle with its center at the point (1, 2) and a radius of 3 units?

To find the equation of a circle, we can use the standard form of a circle’s equation, which is given by:

(x – h)² + (y – k)² = r²

In this equation:

  • (h, k) represents the center of the circle.
  • r represents the radius of the circle.

In your case, the center of the circle is at the point (1, 2). This means:

  • h = 1
  • k = 2

The radius is given as r = 3 units. Now, we need to calculate :

  • r² = 3² = 9

Now we can substitute the values of h, k, and into the standard form equation:

(x – 1)² + (y – 2)² = 9

Thus, the equation of the circle with center (1, 2) and radius 3 is:

(x – 1)² + (y – 2)² = 9

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