What is the equation of the line that passes through the points (0, 4) and (3, 2)?

To find the equation of the line that contains the points (0, 4) and (3, 2), we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

Step 1: Calculate the slope
The slope m of a line through two points, (x1, y1) and (x2, y2), can be calculated using the formula:

m = (y2 – y1) / (x2 – x1)

For our points, we have:

  • (x1, y1) = (0, 4)
  • (x2, y2) = (3, 2)

Substituting in the values:

m = (2 – 4) / (3 – 0) = -2 / 3

Step 2: Find the y-intercept
Now that we have the slope, we can use one of the points to find the y-intercept b. We’ll use the point (0, 4), where x = 0, to find b.

Using the equation of the line:

y = mx + b

Substituting the known values (x = 0, y = 4, m = -2/3):

4 = (-2/3)(0) + b

This simplifies to:

b = 4

Step 3: Write the equation of the line
Now that we have both the slope and the y-intercept, we can write the equation of the line:

y = -2/3x + 4

In conclusion, the equation of the line that contains the points (0, 4) and (3, 2) is:

y = -2/3x + 4

Leave a Comment