What is the probability of tossing a tail and rolling a six with a coin and a number cube?

To find the probability of two independent events happening together, we multiply their individual probabilities. In this scenario, we have:

1. Tossing a Coin: A standard coin has two sides: heads (H) and tails (T). The probability of tossing tails (T) is:

P(Tails) = 1/2

2. Rolling a Number Cube: A typical number cube (or die) has six faces, numbered from 1 to 6. The probability of rolling a six is:

P(Six) = 1/6

Since these two events are independent, we can use the multiplication rule of probability:

P(Tails and Six) = P(Tails) × P(Six)

Now, substituting the values we have:

P(Tails and Six) = (1/2) × (1/6) = 1/12

Therefore, the probability of tossing a tail and rolling a six is 1/12.