What is the product of 2p, 73p², 4p, and 3?

To find the product of the terms 2p, 73p², 4p, and 3, we follow the principles of algebraic multiplication, combining both the numerical coefficients and the variable parts.

First, let’s multiply the numerical coefficients:

  • 2 (from 2p)
  • 73 (from 73p²)
  • 4 (from 4p)
  • 3 (a constant)

The multiplication of the numbers is:

2 × 73 × 4 × 3

Calculating this step-by-step:

  • First, multiply 2 by 73:
  • 2 × 73 = 146
  • Next, multiply the result by 4:
  • 146 × 4 = 584
  • Then, multiply that result by 3:
  • 584 × 3 = 1752

Now we have the numerical coefficient: 1752.

Next, we need to multiply the variable factors:

p (from 2p) × p² (from 73p²) × p (from 4p)

When multiplying variables, we add their exponents. Here, the exponents for p are:

  • p1 (from 2p)
  • p2 (from 73p²)
  • p1 (from 4p)

Thus, we add the exponents:

1 + 2 + 1 = 4

So, we have p4.

Finally, combining both parts (the numerical coefficient and the variable part), the product of the entire expression is:

1752p4.

Therefore, the product of 2p, 73p², 4p, and 3 is 1752p4.

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