What is the quotient of the polynomial expression x³ + 3x² + 3x + 2 divided by another polynomial x² + x + 1?

Understanding the Quotient of Polynomials

To find the quotient of the polynomial expression x³ + 3x² + 3x + 2 divided by x² + x + 1, we will use polynomial long division.

Step 1: Set Up the Division

We want to divide:

x³ + 3x² + 3x + 2

÷ x² + x + 1

Step 2: Divide the Leading Terms

First, we look at the leading term of the dividend () and the leading term of the divisor (). We divide the leading terms:

÷ = x

Step 3: Multiply and Subtract

Now, we multiply the entire divisor by x and subtract this from the original dividend:

x * (x² + x + 1) = x³ + x² + x

Now subtract:

(x³ + 3x² + 3x + 2) – (x³ + x² + x)

This leads to:

2x² + 2x + 2

Step 4: Repeat the Process

Now, we divide the new polynomial (2x² + 2x + 2) by x² + x + 1.

2x² ÷ = 2

Next, multiply by the divisor:
2 * (x² + x + 1) = 2x² + 2x + 2

Subtract again:

(2x² + 2x + 2) – (2x² + 2x + 2) = 0

Step 5: Conclusion

Since we end up with a remainder of 0, we conclude that:

x³ + 3x² + 3x + 2 ÷ x² + x + 1 = x + 2

Therefore, the quotient of the given polynomial expression is x + 2.

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