What is the remainder when the polynomial x³ + 4x² + 12x + 9 is divided by x²?

To find the remainder when the polynomial x³ + 4x² + 12x + 9 is divided by , we can employ the polynomial long division method.

1. **Setup the Division**: Start by setting up the polynomial division. We want to divide x³ + 4x² + 12x + 9 by .

2. **Perform the Division**: When dividing by , we get x. Now, multiply x by and subtract it from the original polynomial:

x³ + 4x² + 12x + 9 
- (x³) 
------------------
      4x² + 12x + 9 

3. **Repeat the Process**: Now, divide 4x² by , which gives you 4. Multiply 4 by and subtract again:

4x² + 12x + 9 
- (4x²) 
------------------
          12x + 9 

4. **Identify the Remainder**: The next step is to note that the term 12x cannot be divided by . Thus, the terms we are left with: 12x + 9 is the remainder since both terms are of lower degree than .

5. **Conclusion**: Therefore, the remainder when dividing x³ + 4x² + 12x + 9 by is:

Remainder: 12x + 9

This remainder holds true regardless of the value of x, as long as we are dealing with polynomial division.

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