What is the result when dividing the polynomial x^3 + 5x^2 + 2x + 5 by x – 2?

To find the quotient when dividing the polynomial x³ + 5x² + 2x + 5 by x – 2, we will use polynomial long division.

1. **Setup:** Write the polynomial you want to divide (the dividend) and the divisor. Here, we’re dividing x³ + 5x² + 2x + 5 by x – 2.

2. **First Division:** Divide the leading term of the dividend (x³) by the leading term of the divisor (x), which gives you . Place this above the long division line.

3. **Multiply and Subtract:** Multiply by the entire divisor (x – 2), which results in x³ – 2x². Subtract this from the original polynomial:

  • x³ + 5x² + 2x + 5
  • – (x³ – 2x²)

This gives you 7x² + 2x + 5.

4. **Second Division:** Now repeat the process. Divide the leading term of your new polynomial (7x²) by the leading term of the divisor (x). This gives you 7x. Place that above the division line.

5. **Multiply and Subtract Again:** Multiply 7x by the divisor (x – 2), giving you 7x² – 14x. Subtract this from 7x² + 2x + 5:

  • 7x² + 2x + 5
  • – (7x² – 14x)

This simplifies to 16x + 5.

6. **Final Division:** Divide the new leading term (16x) by the leading term of the divisor (x), resulting in 16. Write 16 above the division line.

7. **Final Multiply and Subtract:** Multiply 16 by (x – 2), resulting in 16x – 32. Subtract this from 16x + 5:

  • 16x + 5
  • – (16x – 32)

When you do this, you obtain a remainder of 37.

8. **Result:** Therefore, the quotient when x³ + 5x² + 2x + 5 is divided by x – 2 is x² + 7x + 16 with a remainder of 37.

So, you can express the final answer as:

Quotient: x² + 7x + 16, Remainder: 37

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