What is the solution set for the system of equations 2y = x + 3 and 5y = x + 7?

To find the solution set for the given system of equations, we need to solve the two equations simultaneously. The equations given are:

  • Equation 1: 2y = x + 3
  • Equation 2: 5y = x + 7

We can start by manipulating these equations to express ‘y’ in terms of ‘x’.

Step 1: Rearranging Equation 1

From Equation 1:

2y = x + 3

we isolate ‘y’:

y = (x + 3) / 2

Step 2: Substituting into Equation 2

Now that we have ‘y’ in terms of ‘x’, we’ll substitute this expression into Equation 2:

5y = x + 7

Substituting for ‘y’:

5((x + 3) / 2) = x + 7

Now, we simplify the equation:

(5(x + 3)) / 2 = x + 7

Multiplying both sides by 2 to eliminate the fraction:

5(x + 3) = 2(x + 7)
5x + 15 = 2x + 14

Step 3: Solving for ‘x’

Next, we rearrange to get all terms involving ‘x’ on one side:

5x - 2x = 14 - 15
3x = -1

Now, we solve for ‘x’:

x = -1/3

Step 4: Finding ‘y’

Now that we have ‘x’, we need to find the corresponding ‘y’ value using our expression for ‘y’:

y = ((-1/3) + 3) / 2

To simplify:

y = (8/3) / 2 = 8/6 = 4/3

Conclusion

The solution for the system of equations is:

(x, y) = (-1/3, 4/3)

Thus, the solution set is: { (-1/3, 4/3) }

Leave a Comment