The sequence defined by the formula 3n + 3 can be expressed by substituting the values of n starting from 1. Let’s derive the first 10 terms:
- For n = 1: 3(1) + 3 = 6
- For n = 2: 3(2) + 3 = 9
- For n = 3: 3(3) + 3 = 12
- For n = 4: 3(4) + 3 = 15
- For n = 5: 3(5) + 3 = 18
- For n = 6: 3(6) + 3 = 21
- For n = 7: 3(7) + 3 = 24
- For n = 8: 3(8) + 3 = 27
- For n = 9: 3(9) + 3 = 30
- For n = 10: 3(10) + 3 = 33
Now, let’s list the first 10 terms:
- Term 1: 6
- Term 2: 9
- Term 3: 12
- Term 4: 15
- Term 5: 18
- Term 6: 21
- Term 7: 24
- Term 8: 27
- Term 9: 30
- Term 10: 33
Next, we can sum these values:
Sum = 6 + 9 + 12 + 15 + 18 + 21 + 24 + 27 + 30 + 33
Calculating this step by step gives:
- 6 + 9 = 15
- 15 + 12 = 27
- 27 + 15 = 42
- 42 + 18 = 60
- 60 + 21 = 81
- 81 + 24 = 105
- 105 + 27 = 132
- 132 + 30 = 162
- 162 + 33 = 195
Therefore, the sum of the first 10 terms of the sequence defined by 3n + 3 is 195.