What is the sum of the geometric sequence 4, 24, 144 given that there are 8 terms?

The sum of a geometric sequence can be calculated using the formula:

Sn = a1 × \frac{(r^n – 1)}{(r – 1)}

Where:

  • Sn is the sum of the first n terms.
  • a1 is the first term of the sequence.
  • r is the common ratio.
  • n is the number of terms.

In this case, the first term (a1) is 4. To find the common ratio (r), we can divide the second term by the first term.

r = \frac{a2}{a1} = \frac{24}{4} = 6

Now we can proceed to find the sum of the first 8 terms (n = 8):

S8 = 4 × \frac{(6^8 – 1)}{(6 – 1)}

Calculating (6^8):

6^8 = 1679616

Now, we substitute back into the equation:

S8 = 4 × \frac{(1679616 – 1)}{5}

Calculating further:

= 4 × \frac{1679615}{5}

= 4 × 335923

= 1343692

Hence, the sum of the geometric sequence with the first 8 terms is 1,343,692.

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