What is the value of f(g(x)) if f(x) is defined as x^4 + x^3 + x^2 and g(x) is defined as x^2, where x is not equal to 0?

To find f(g(x)), we first need to determine what g(x) is when we substitute a value for x.

Given that g(x) = x^2, we can compute it by plugging in any valid value for x. Let’s keep it simple and use x = a (where a is any number other than 0), thus g(a) = a^2.

Now, we will substitute g(a) into the function f(x). The function f(x) is defined as:

 f(x) = x^4 + x^3 + x^2 

Replacing x in this function with g(a) = a^2, we have:

 f(g(a)) = f(a^2) = (a^2)^4 + (a^2)^3 + (a^2)^2 

This simplifies to:

 f(a^2) = a^8 + a^6 + a^4 

Thus, the final result for f(g(x)) is:

 f(g(x)) = x^8 + x^6 + x^4 

In conclusion, replacing x in f(g(x)) with x^2 leads us to the simplified expression:

x^8 + x^6 + x^4.

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