To solve for f(x) when x = 5, we first need to understand the function f(x). In this case, it is assumed that f(x) = 5 imes 40, which is a constant multiplication of the two numbers regardless of the value of x.
Calculating 5 imes 40, we get:
- 5 imes 40 = 200
Since f(x) is not dependent on the value of x and is always equal to 200, we can conclude that:
f(5) = 200
Thus, when x = 5, the value of the function f(x) remains 200.