What is the value of x in the following system of equations: 2y + 6 = 6y + x and x = 18?

To solve the system of equations given by:

We start by substituting the value of x from Equation 2 into Equation 1.

Substituting x = 18 into Equation 1:

2y + 6 = 6y + 18

Now, we will simplify this equation:

First, let’s move all terms involving y to one side and constant terms to the other:

2y - 6y = 18 - 6

This simplifies to:

-4y = 12

Next, we solve for y by dividing both sides by -4:

y = -3

We have found that y = -3. However, since the question specifically asks for the value of x, we can refer back to Equation 2 where we defined:

x = 18.

Thus, the value of x in this system of equations is:

x = 18.

In conclusion, the value of x is 18.