To find the exact solution to the system of equations given by y = 6075x and y = 4x + 1, we can set the equations equal to each other since they both describe the variable y.
1. Start by substituting 6075x for y in the second equation:
6075x = 4x + 1
2. Next, isolate the variable x:
6075x - 4x = 1
3. This simplifies to:
6071x = 1
4. Now, divide both sides by 6071:
x = \frac{1}{6071}
5. With the value of x determined, we can now substitute this back into either equation to find the corresponding value of y. We will use the first equation:
y = 6075 * (\frac{1}{6071})
6. This simplifies to:
y = \frac{6075}{6071}
7. Therefore, the solution to the system of equations is:
(x, y) = \left(\frac{1}{6071}, \frac{6075}{6071}\right)
In conclusion, the exact point that is a solution to the given system of equations is:
\left(\frac{1}{6071}, \frac{6075}{6071}\right)
This indicates the values of x and y that satisfy both equations simultaneously.