What value of n makes the expression x² + 11x + n a perfect square trinomial?

To determine the value of n that makes the expression x² + 11x + n a perfect square trinomial, we can use the formula for a perfect square trinomial.

A perfect square trinomial can be expressed in the general form of:

  • (a + b)² = a² + 2ab + b²

Here, a is the coefficient of the x term and b is a constant. In our case, the coefficient of x is 11, relating to our perfect square trinomial.

The value of b can be derived by the equation:

  • 2b = 11

Now, solving for b, we have:

  • b = 11/2 = 5.5

Next, to find the value of n, we need to calculate :

  • n = b²

Substituting the value of b:

  • n = (5.5)² = 30.25

Thus, the value of n that makes the expression x² + 11x + n a perfect square trinomial is 30.25. This means the expression can be rewritten as:

  • (x + 5.5)²

In conclusion, encapsulating the necessary steps, we find that:

  • The value of n is 30.25

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