What value of the constant c ensures that the function f is continuous at all points, specifically at x = 2 and x = 3?

To determine the value of the constant c that makes the function f continuous, we need to analyze the function at the points where the definition changes. The function is defined as:

  • f(x) = cx2 + 2x + 1 for x < 2
  • f(x) = cx for x > 2

The function will be continuous at a point if the limit of f(x) as x approaches that point from both sides equals the function’s value at that point.

Step 1: Ensure Continuity at x = 2

We begin with ensuring the function is continuous at x = 2. We need to find:

  • Limit from the left:
    lim (x -> 2-) f(x) = c(2)2 + 2(2) + 1 = 4c + 4 + 1 = 4c + 5
  • Limit from the right:
    lim (x -> 2+) f(x) = c(2) = 2c

Setting these equal for continuity:

4c + 5 = 2c

Simplifying gives:

4c - 2c + 5 = 0
2c + 5 = 0
2c = -5
c = - rac{5}{2}

Step 2: Ensure Continuity at x = 3

Next, we check the continuity at x = 3:
We need to find:

  • Limit from the left:
    lim (x -> 3-) f(x) = c(32) + 2(3) + 1 = 9c + 6 + 1 = 9c + 7
  • Limit from the right:
    lim (x -> 3+) f(x) = c(3) = 3c

Setting these equal for continuity:

9c + 7 = 3c

Simplifying gives:

9c - 3c + 7 = 0
6c + 7 = 0
6c = -7
c = - rac{7}{6}

Conclusion

At this point, we derive two different values for c based on the respective continuity requirements:
– For the function to be continuous at x = 2, we find c = - rac{5}{2} and
– For x = 3, c = - rac{7}{6}.

Since these values are not equal, the function cannot be continuous at both points simultaneously for any single c. Therefore, there isn’t a single value for c that would make the function f continuous at both points x = 2 and x = 3.

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