What values of b satisfy the equation 43b^2 + 2 = 64?

To find the values of b that satisfy the equation 43b² + 2 = 64, we first need to isolate the term. We can do this by following these steps:

  1. Subtract 2 from both sides:
  2. This gives us:

    43b² = 64 - 2

    Which simplifies to:

    43b² = 62
  3. Next, divide both sides by 43:
  4. b² = 62 / 43

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  5. Now, we take the square root of both sides:
  6. b = ±√(62 / 43)

    This results in two potential solutions for b:

    • b = √(62/43)
    • b = -√(62/43)

To provide numerical approximations:

  • Calculating √(62 / 43) gives us approximately 1.041.
  • Thus, the two values of b can be rounded to approximately 1.041 and -1.041.

In conclusion, the values of b that satisfy the equation 43b² + 2 = 64 are approximately:

  • b ≈ 1.041
  • b ≈ -1.041

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