When is a point considered a solution to a system of two inequalities?

A point is considered a solution to a system of two inequalities if it satisfies both inequalities simultaneously. In simpler terms, for a point (x, y) to be a solution:

  • It must be located within the region defined by the solutions of both inequalities.
  • The point must comply with the conditions set by each individual inequality in the system.
  • If the inequalities are written in the form of:

y > mx + b

y < nx + d

The point (x, y) must satisfy both
y > mx + b and y < nx + d.

To illustrate:

  1. Example 1: For the inequalities y > 2x + 1 and y < -x + 3, the point (1, 3) can be analyzed:
    • Substituting into the first inequality: 3 > 2(1) + 13 > 3 (not true)
    • Substituting into the second inequality: 3 < -1 + 33 < 2 (not true)
  2. This point does not satisfy both inequalities, hence it is not a solution.
  1. Example 2: For the same inequalities above, consider the point (0, 2):
    • For the first inequality: 2 > 2(0) + 12 > 1 (true)
    • For the second inequality: 2 < -0 + 32 < 3 (true)
  2. Since (0, 2) satisfies both inequalities, it is considered a solution to the system.

In conclusion, checking whether the point satisfies each inequality will determine if it is part of the solution set for the given system of inequalities.

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