When x is 3 and y is 5, how much does the value of 3x² + 2y exceed the value of 2x² + 3y?

To solve the problem, we first need to substitute the values of x and y into the expressions given:

1. **Calculate 3x² + 2y:**

  • Substituting x = 3 and y = 5, we get:
  • 3(3²) + 2(5)
  • 3(9) + 10 = 27 + 10 = 37

2. **Calculate 2x² + 3y:**

  • Substituting x = 3 and y = 5, we have:
  • 2(3²) + 3(5)
  • 2(9) + 15 = 18 + 15 = 33

3. **Find the excess of 3x² + 2y over 2x² + 3y:**

  • Now, we calculate how much 3x² + 2y exceeds 2x² + 3y:
  • 37 – 33 = 4

Therefore, the value of 3x² + 2y exceeds the value of 2x² + 3y by 4.

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