Which of the following functions is an even function: f(x) = x, f(x) = x^3 + 1, or f(x) = 3x?

An even function is one that satisfies the condition f(-x) = f(x) for all values of x within its domain. This means that the function’s graph is symmetric with respect to the y-axis.

Let’s evaluate each of the given functions to determine if they are even:

1. For f(x) = x:

To check if this is an even function, we calculate:

f(-x) = -x

Since f(-x) ≠ f(x), this function is not even.

2. For f(x) = x³ + 1:

Now, we will check:

f(-x) = (-x)³ + 1 = -x³ + 1

Since f(-x) ≠ f(x), this function is also not even.

3. For f(x) = 3x:

Checking yields:

f(-x) = 3(-x) = -3x

Where f(-x) ≠ f(x), indicating that this function is also not even.

Conclusion:

None of the functions listed (f(x) = x, f(x) = x³ + 1, or f(x) = 3x) are even functions.

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